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70 lines
1.8 KiB
Plaintext
70 lines
1.8 KiB
Plaintext
---
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title: '11. Container With Most Water'
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description: You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the i^th line are (i, 0) and (i, height[i])
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icon: dot
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topics:
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- { name: "Array", slug: "array" }
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- { name: "Two Pointers", slug: "two-pointers" }
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- { name: "Greedy", slug: "greedy" }
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video: "UuiTKBwPgAo"
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issue: "https://github.com/prdlk/leetcode/issues/44"
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sidebar:
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label: 'Container With Most Water'
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badge: 'Medium'
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---
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::::warning
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Notice that you may not slant the container.
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::::
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### Example 1:
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- Input: `height = [1,8,6,2,5,4,8,3,7]`
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- Output: `49`
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- Explanation: The above vertical lines are represented by array `[1,8,6,2,5,4,8,3,7]`. In this case, the max area of water (blue section) the container can contain is `49`.
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### Example 2:
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- Input: `height = [1,1]`
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- Output: `1`
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### Constraints:
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- `n == height.length`
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- `2 <= n <= 10^5`
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- `0 <= height[i] <= 10^4`
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## Approach
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```mermaid
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flowchart TD
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S(["maxArea(height)"]) --> I["res = 0, left = 0, right = len - 1"]
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I --> W{"left < right?"}
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W -- no --> E(["return res"])
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W -- yes --> A["area = (right - left) * min(height[left], height[right])"]
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A --> M["res = max(res, area)"]
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M --> C{"height[left] < height[right]?"}
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C -- yes --> L["left += 1 — drop the shorter wall"]
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C -- no --> R["right -= 1 — drop the shorter wall"]
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L --> W
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R --> W
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```
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## Solution
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```py
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class Solution:
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def maxArea(self, height: List[int]) -> int: # noqa: F821
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res = 0
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left = 0
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right = len(height) - 1
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while left < right:
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area = (right - left) * min(height[left], height[right])
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res = max(res, area)
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if height[left] < height[right]:
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left += 1
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else:
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right -= 1
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return res
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```
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