feat(work): add Course Schedule II solution and clean up Course Schedule I implementation

apps/docs/content/topological-sort/210-course-schedule-ii.mdx

@@ -0,0 +1,39 @@
+---
+title: '210. Course Schedule II'
+description: There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must take course bi first if you want to take course ai
+sidebar:
+  label: 'Course Schedule II'
+  badge: 'Medium'
+---
+
+<Badge variant="accent">Depth-First Search</Badge>
+
+### Example 1:
+- Input: `numCourses = 2, prerequisites = [[1,0]]`
+- Output: `[0,1]`
+- Explanation: There are a total of `2` courses to take. To take course `1` you should have finished course `0`. So the correct course order is `[0,1]`.
+
+### Example 2:
+- Input: `numCourses = 4, prerequisites = [[1,0],[2,0],[3,1],[3,2]]`
+- Output: `[0,2,1,3]`
+- Explanation: There are a total of `4` courses to take. To take course `3` you should have finished both courses `1` and `2`. Both courses `1` and `2` should be taken after you finished course `0`. So one correct course order is `[0,1,2,3]`. Another correct ordering is `[0,2,1,3]`.
+
+### Example 3:
+- Input: `numCourses = 1, prerequisites = []`
+- Output: `[0]`
+
+### Constraints:
+
+- `1 <= numCourses <= 2000`
+- `0 <= prerequisites.length <= numCourses * (numCourses - 1)`
+- `prerequisites[i].length == 2`
+- `0 <= ai, bi < numCourses`
+- `ai != bi`
+- All the pairs [ai, bi] are distinct.
+
+## Solution
+
+```py
+class Solution:
+    def findOrder(self, numCourses: int, prerequisites: list[list[int]]) -> list[int]:
+```