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feat(work): implement reorder list solution for problem 143
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@@ -18,7 +18,7 @@ L0 → Ln → L1 → Ln - 1 → L2 → Ln - 2 →
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You may not modify the values in the list's nodes. Only nodes
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You may not modify the values in the list's nodes. Only nodes
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themselves may be changed.
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themselves may be changed.
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Example 1:
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Example 1:
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@@ -30,15 +30,16 @@ Example 2:
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Input: head = [1,2,3,4,5]
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Input: head = [1,2,3,4,5]
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Output: [1,5,2,4,3]
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Output: [1,5,2,4,3]
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Constraints:
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Constraints:
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• The number of nodes in the list is in the range [1, 5 * 10^4].
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• The number of nodes in the list is in the range [1, 5 * 10^4].
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• 1 <= Node.val <= 1000
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• 1 <= Node.val <= 1000
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"""
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"""
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# Definition for singly-linked list.
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# Definition for singly-linked list.
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# class ListNode:
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# def __init__(self, val=0, next=None):
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@@ -46,7 +47,25 @@ Constraints:
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# self.next = next
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# self.next = next
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class Solution:
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class Solution:
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def reorderList(self, head: ListNode | None) -> None:
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def reorderList(self, head: ListNode | None) -> None:
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"""
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# Find middle
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Do not return anything, modify head in-place instead.
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slow, fast = head, head.next
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"""
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while fast and fast.next:
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slow = slow.next
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fast = fast.next.next
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# Reverse second half
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second = slow.next
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prev = slow.next = None
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while second:
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tmp = second.next
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second.next = prev
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prev = second
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second = tmp
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# merge two halfs
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first, second = head, prev
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while second:
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tmp1, tmp2 = first.next, second.next
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first.next = second
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second.next = tmp1
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first, second = tmp1, tmp2
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