feat(work): implement reorder list solution for problem 143

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Prad Nukala committed 2026-10-14 11:04:19 -04:00
1 parent 37a2d39269
commit 886024c4f0
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+27 -8
+27 -8
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@@ -18,7 +18,7 @@ L0 → Ln → L1 → Ln - 1 → L2 → Ln - 2 →
You may not modify the values in the list's nodes. Only nodes
themselves may be changed.
Example 1:
@@ -30,15 +30,16 @@ Example 2:
Input: head = [1,2,3,4,5]
Output: [1,5,2,4,3]
Constraints:
• The number of nodes in the list is in the range [1, 5 * 10^4].
• The number of nodes in the list is in the range [1, 5 * 10^4].
• 1 <= Node.val <= 1000
• 1 <= Node.val <= 1000
"""
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
@@ -46,7 +47,25 @@ Constraints:
# self.next = next
class Solution:
def reorderList(self, head: ListNode | None) -> None:
"""
Do not return anything, modify head in-place instead.
"""
# Find middle
slow, fast = head, head.next
while fast and fast.next:
slow = slow.next
fast = fast.next.next
# Reverse second half
second = slow.next
prev = slow.next = None
while second:
tmp = second.next
second.next = prev
prev = second
second = tmp
# merge two halfs
first, second = head, prev
while second:
tmp1, tmp2 = first.next, second.next
first.next = second
second.next = tmp1
first, second = tmp1, tmp2