mirror of
https://github.com/prdlk/leetcode.git
synced 2026-09-17 07:26:27 +00:00
feat(work): add Set Matrix Zeroes solution
This commit is contained in:
@@ -0,0 +1,81 @@
|
||||
"""
|
||||
73. Set Matrix Zeroes
|
||||
Difficulty: Medium
|
||||
https://leetcode.com/problems/set-matrix-zeroes/
|
||||
|
||||
──────────────────────────────────────────────────
|
||||
|
||||
Given an m x n integer matrix matrix, if an element is 0, set its
|
||||
entire row and column to 0's.
|
||||
|
||||
You must do it in place.
|
||||
|
||||
|
||||
|
||||
Example 1:
|
||||
|
||||
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]]
|
||||
Output: [[1,0,1],[0,0,0],[1,0,1]]
|
||||
|
||||
Example 2:
|
||||
|
||||
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
|
||||
Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
|
||||
|
||||
|
||||
|
||||
Constraints:
|
||||
|
||||
• m == matrix.length
|
||||
|
||||
• n == matrix[0].length
|
||||
|
||||
• 1 <= m, n <= 200
|
||||
|
||||
• -2^31 <= matrix[i][j] <= 2^31 - 1
|
||||
|
||||
|
||||
|
||||
Follow up:
|
||||
|
||||
• A straightforward solution using O(mn) space is probably a bad
|
||||
idea.
|
||||
|
||||
• A simple improvement uses O(m + n) space, but still not the best
|
||||
solution.
|
||||
|
||||
• Could you devise a constant space solution?
|
||||
"""
|
||||
|
||||
|
||||
class Solution:
|
||||
def setZeroes(self, matrix: List[List[int]]) -> None:
|
||||
"""
|
||||
Do not return anything, modify matrix in-place instead.
|
||||
"""
|
||||
m, n = len(matrix), len(matrix[0])
|
||||
|
||||
# 1. remember if row 0 or column 0 have their own zeros
|
||||
row0_zero = any(matrix[0][c] == 0 for c in range(n))
|
||||
col0_zero = any(matrix[r][0] == 0 for r in range(m))
|
||||
|
||||
# 2. use row 0 and column 0 as marker lists
|
||||
for r in range(1, m):
|
||||
for c in range(1, n):
|
||||
if matrix[r][c] == 0:
|
||||
matrix[r][0] = 0
|
||||
matrix[0][c] = 0
|
||||
|
||||
# 3. zero the inner cells from the markers
|
||||
for r in range(1, m):
|
||||
for c in range(1, n):
|
||||
if matrix[r][0] == 0 or matrix[0][c] == 0:
|
||||
matrix[r][c] = 0
|
||||
|
||||
# 4. handle row 0 and column 0 last
|
||||
if row0_zero:
|
||||
for c in range(n):
|
||||
matrix[0][c] = 0
|
||||
if col0_zero:
|
||||
for r in range(m):
|
||||
matrix[r][0] = 0
|
||||
Reference in New Issue
Block a user