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---
title: '224. Basic Calculator'
description: Given a string s representing a valid expression, implement a basic calculator to evaluate it, and return the result of the evaluation
icon: dot
topics:
- { name: "Math", slug: "math" }
- { name: "String", slug: "string" }
- { name: "Stack", slug: "stack" }
- { name: "Recursion", slug: "recursion" }
issue: "https://github.com/prdlk/leetcode/issues/71"
companies:
- { name: "Bloomberg", period: "Three Months", frequency: 54 }
- { name: "Microsoft", period: "Three Months", frequency: 42.1 }
- { name: "Amazon", period: "Three Months", frequency: 28.9 }
- { name: "Google", period: "Three Months", frequency: 23.9 }
- { name: "Meta", period: "Six Months", frequency: 24.5 }
sidebar:
label: 'Basic Calculator'
badge: 'Hard'
---
### Example 1:
- Input: `s = "1 + 1"`
- Output: `2`
### Example 2:
- Input: `s = " 2-1 + 2 "`
- Output: `3`
### Example 3:
- Input: `s = "(1+(4+5+2)-3)+(6+8)"`
- Output: `23`
### Constraints:
- `1 <= s.length <= 3 * 10^5`
- `s` consists of digits, '+', '-', '(', ')', and ' '.
- `s` represents a valid expression.
- '+' is not used as a unary operation (i.e., "+1" and "+(2 + 3)" is invalid).
- '-' could be used as a unary operation (i.e., "-1" and "-(2 + 3)" is valid).
- There will be no two consecutive operators in the input.
- Every number and running calculation will fit in a signed 32-bit integer.
## Solution
```py
class Solution:
def calculate(self, s: str) -> int:
```