mirror of
https://github.com/prdlk/leetcode.git
synced 2026-11-02 13:12:44 +00:00
57 lines
1.4 KiB
Python
57 lines
1.4 KiB
Python
"""
|
|
56. Merge Intervals
|
|
Difficulty: Medium
|
|
https://leetcode.com/problems/merge-intervals/
|
|
|
|
──────────────────────────────────────────────────
|
|
|
|
Given an array of intervals where intervals[i] = [starti, endi],
|
|
merge all overlapping intervals, and return an array of the
|
|
non-overlapping intervals that cover all the intervals in the input.
|
|
|
|
|
|
|
|
Example 1:
|
|
|
|
Input: intervals = [[1,3],[2,6],[8,10],[15,18]]
|
|
Output: [[1,6],[8,10],[15,18]]
|
|
Explanation: Since intervals [1,3] and [2,6] overlap, merge them into
|
|
[1,6].
|
|
|
|
Example 2:
|
|
|
|
Input: intervals = [[1,4],[4,5]]
|
|
Output: [[1,5]]
|
|
Explanation: Intervals [1,4] and [4,5] are considered overlapping.
|
|
|
|
Example 3:
|
|
|
|
Input: intervals = [[4,7],[1,4]]
|
|
Output: [[1,7]]
|
|
Explanation: Intervals [1,4] and [4,7] are considered overlapping.
|
|
|
|
|
|
|
|
Constraints:
|
|
|
|
• 1 <= intervals.length <= 10^4
|
|
|
|
• intervals[i].length == 2
|
|
|
|
• 0 <= starti <= endi <= 10^4
|
|
"""
|
|
|
|
|
|
class Solution:
|
|
def merge(self, intervals: list[list[int]]) -> list[list[int]]:
|
|
intervals.sort(key=lambda x: x[0])
|
|
result = []
|
|
|
|
for start, end in intervals:
|
|
if result and start <= result[-1][1]:
|
|
result[-1][1] = max(result[-1][1], end)
|
|
else:
|
|
result.append([start, end])
|
|
|
|
return result
|