Files
leetcode/apps/docs/content/(array)/217-contains-duplicate.mdx
T

65 lines
1.3 KiB
Plaintext

---
title: '217. Contains Duplicate'
description: Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct
sidebar:
label: 'Contains Duplicate'
badge: 'Easy'
---
<Badge variant="accent">Hash Table</Badge>
### Example 1:
- Input: `nums = [1,2,3,1]`
- Output: `true`
- Explanation: The element `1` occurs at the indices `0` and `3`.
### Example 2:
- Input: `nums = [1,2,3,4]`
- Output: `false`
- Explanation: All elements are distinct.
### Example 3:
- Input: `nums = [1,1,1,3,3,4,3,2,4,2]`
- Output: `true`
### Constraints:
- `1 <= nums.length <= 10^5`
- `-10^9 <= nums[i] <= 10^9`
## Approach
```mermaid
flowchart TD
S(["containsDuplicate(nums)"]) --> I["freq = {}"]
I --> L{"more n in nums?"}
L -- no --> E(["return false"])
L -- yes --> C["freq[n] = (freq[n] or 0) + 1"]
C --> Q{"freq[n] >= 2?"}
Q -- yes --> R(["return true"])
Q -- no --> L
```
## Solution
```js
/**
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = function(nums) {
const freq = {};
for (let n of nums) {
freq[n] = (freq[n] || 0) + 1;
if (freq[n] >= 2) {
return true;
}
}
return false;
};
```
## Explanation
<YouTube id="3OamzN90kPg" title="Contains Duplicate - Leetcode 217 - Python" />