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56 lines
1.6 KiB
Plaintext
56 lines
1.6 KiB
Plaintext
---
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title: '167. Two Sum II - Input Array Is Sorted'
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description: Given a 1-indexed array of integers numbers that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target number. Let these two numbers be numbers[index1] and numbers[index2] where 1 <= index1 < index2 <= numbers.length
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sidebar:
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label: 'Two Sum II - Input Array Is Sorted'
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badge: 'Medium'
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---
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<Badge variant="accent">Two Pointers</Badge>
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::::warning
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Your solution must use only constant extra space.
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::::
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### Example 1:
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- Input: `numbers = [2,7,11,15], target = 9`
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- Output: `[1,2]`
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- Explanation: The sum of `2` and `7` is `9`. Therefore, `index1 = 1`, `index2 = 2`. We return `[1, 2]`.
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### Example 2:
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- Input: `numbers = [2,3,4], target = 6`
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- Output: `[1,3]`
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- Explanation: The sum of `2` and `4` is `6`. Therefore `index1 = 1`, `index2 = 3`. We return `[1, 3]`.
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### Example 3:
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- Input: `numbers = [-1,0], target = -1`
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- Output: `[1,2]`
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- Explanation: The sum of `-1` and `0` is `-1`. Therefore `index1 = 1`, `index2 = 2`. We return `[1, 2]`.
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### Constraints:
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- `2 <= numbers.length <= 3 * 10^4`
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- `-1000 <= numbers[i] <= 1000`
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- `numbers` is sorted in non-decreasing order.
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- `-1000 <= target <= 1000`
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- The tests are generated such that there is exactly one solution.
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## Solution
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```py
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class Solution:
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def twoSum(self, numbers: List[int], target: int) -> List[int]:
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i = 0
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j = len(numbers) - 1
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while i < j:
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c = numbers[i] + numbers[j]
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if c == target:
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return [i + 1, j + 1]
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elif c < target:
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i+=1
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else:
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j-=1
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return []
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```
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