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---
title: '48. Rotate Image'
description: You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise)
icon: line-dot-left-horizontal
sidebar:
label: 'Rotate Image'
badge: 'Medium'
---
<Badge variant="accent">Array</Badge>
### Example 1:
- Input: `matrix = [[1,2,3],[4,5,6],[7,8,9]]`
- Output: `[[7,4,1],[8,5,2],[9,6,3]]`
### Example 2:
- Input: `matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]`
- Output: `[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]`
### Constraints:
- `n == matrix.length == matrix[i].length`
- `1 <= n <= 20`
- `-1000 <= matrix[i][j] <= 1000`
## Approach
```mermaid
flowchart TD
S(["rotate(matrix)"]) --> N["n = len(matrix)"]
N --> F{"more r in range(n)?"}
F -- yes --> G{"more c in range(r + 1, n)?"}
G -- yes --> T["swap matrix[r][c] and matrix[c][r] — transpose across the diagonal"]
T --> G
G -- no --> F
F -- no --> H{"more r in range(n)?"}
H -- yes --> R["matrix[r].reverse() — transpose then mirror is a clockwise turn"]
R --> H
H -- no --> E(["return None — rotated in place"])
```
## Solution
```py
class Solution:
def rotate(self, matrix: List[List[int]]) -> None:
n = len(matrix)
for r in range(n):
for c in range(r + 1, n):
matrix[r][c], matrix[c][r] = matrix[c][r], matrix[r][c]
for r in range(n):
matrix[r].reverse()
```
## Explanation
<YouTube id="fMSJSS7eO1w" title="Rotate Image - Matrix - Leetcode 48" />