mirror of
https://github.com/prdlk/leetcode.git
synced 2026-11-02 13:12:44 +00:00
51 lines
1.1 KiB
Python
51 lines
1.1 KiB
Python
"""
|
|
876. Middle of the Linked List
|
|
Difficulty: Easy
|
|
https://leetcode.com/problems/middle-of-the-linked-list/
|
|
|
|
──────────────────────────────────────────────────
|
|
|
|
Given the head of a singly linked list, return the middle node of the
|
|
linked list.
|
|
|
|
If there are two middle nodes, return the second middle node.
|
|
|
|
|
|
|
|
Example 1:
|
|
|
|
Input: head = [1,2,3,4,5]
|
|
Output: [3,4,5]
|
|
Explanation: The middle node of the list is node 3.
|
|
|
|
Example 2:
|
|
|
|
Input: head = [1,2,3,4,5,6]
|
|
Output: [4,5,6]
|
|
Explanation: Since the list has two middle nodes with values 3 and 4,
|
|
we return the second one.
|
|
|
|
|
|
|
|
Constraints:
|
|
|
|
• The number of nodes in the list is in the range [1, 100].
|
|
|
|
• 1 <= Node.val <= 100
|
|
"""
|
|
|
|
|
|
# Definition for singly-linked list.
|
|
# class ListNode:
|
|
# def __init__(self, val=0, next=None):
|
|
# self.val = val
|
|
# self.next = next
|
|
class Solution:
|
|
def middleNode(self, head: ListNode | None) -> ListNode | None:
|
|
slow = fast = head
|
|
while fast and fast.next:
|
|
fast = fast.next.next
|
|
slow = slow.next
|
|
|
|
return slow
|