Files
leetcode/work/1/Medium/Depth-First Search/323.number-of-connected-components-in-an-undirected-graph.py

70 lines
1.6 KiB
Python

"""
323. Number of Connected Components in an Undirected Graph
Difficulty: Medium
https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/
──────────────────────────────────────────────────
You have a graph of n nodes. You are given an integer n and an array
edges where edges[i] = [ai, bi] indicates that there is an edge
between ai and bi in the graph.
Return the number of connected components in the graph.
Example 1:
Input: n = 5, edges = [[0,1],[1,2],[3,4]]
Output: 2
Example 2:
Input: n = 5, edges = [[0,1],[1,2],[2,3],[3,4]]
Output: 1
Constraints:
• 1 <= n <= 2000
• 1 <= edges.length <= 5000
• edges[i] = [ai, bi]
• ai != bi
• There are no repeated edges.
"""
class Solution:
def countComponents(self, n: int, edges: list[list[int]]) -> int:
par = [i for i in range(n + 1)]
rank = [1] * (n + 1)
def find(n):
res = n
while res != par[res]:
par[res] = par[par[res]]
res = par[res]
return res
def union(n1, n2):
p1, p2 = find(n1), find(n2)
if p1 == p2:
return 0
if rank[p1] > rank[p2]:
par[p2] = p1
rank[p1] += rank[p2]
else:
par[p1] = p2
rank[p2] += rank[p1]
return 1
res = n
for n1, n2 in edges:
res -= union(n1, n2)
return res