---
title: '33. Search in Rotated Sorted Array'
description: There is an integer array nums sorted in ascending order (with distinct values)
sidebar:
label: 'Search in Rotated Sorted Array'
badge: 'Medium'
---
Array
::::warning
You must write an algorithm with O(log n) runtime complexity.
::::
### Example 1:
- Input: `nums = [4,5,6,7,0,1,2], target = 0`
- Output: `4`
### Example 2:
- Input: `nums = [4,5,6,7,0,1,2], target = 3`
- Output: `-1`
### Example 3:
- Input: `nums = [1], target = 0`
- Output: `-1`
### Constraints:
- `1 <= nums.length <= 5000`
- `-10^4 <= nums[i] <= 10^4`
- All values of `nums` are unique.
- `nums` is an ascending array that is possibly rotated.
- `-10^4 <= target <= 10^4`
## Approach
```mermaid
flowchart TD
S(["search(nums, target)"]) --> I["l = 0, r = n - 1"]
I --> W{"l <= r?"}
W -- no --> E(["return -1"])
W -- yes --> M["mid = floor((l + r) / 2)"]
M --> F{"nums[mid] == target?"}
F -- yes --> R(["return mid"])
F -- no --> H{"nums[l] <= nums[mid]? — left half sorted"}
H -- yes --> A{"target outside [nums[l], nums[mid]]?"}
A -- yes --> A1["l = mid + 1 — search the right half"]
A -- no --> A2["r = mid - 1"]
H -- no --> B{"target outside [nums[mid], nums[r]]?"}
B -- yes --> B1["r = mid - 1 — search the left half"]
B -- no --> B2["l = mid + 1"]
A1 --> W
A2 --> W
B1 --> W
B2 --> W
```
## Solution
```js
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
var search = function(nums, target) {
let l = 0, r = nums.length - 1;
while (l <= r){
let mid = Math.floor((l + r)/2);
if (target === nums[mid]) {
return mid
}
// Left sorted portion
if (nums[l] <= nums[mid]){
if (target > nums[mid] || target < nums[l]){
l = mid + 1;
}else{
r = mid - 1;
}
}
// Right sorted portion
else{
if(target < nums[mid] || target > nums[r]){
r = mid - 1;
}else{
l = mid + 1;
}
}
}
return -1;
};
```
## Explanation