""" 876. Middle of the Linked List Difficulty: Easy https://leetcode.com/problems/middle-of-the-linked-list/ ────────────────────────────────────────────────── Given the head of a singly linked list, return the middle node of the linked list. If there are two middle nodes, return the second middle node. Example 1: Input: head = [1,2,3,4,5] Output: [3,4,5] Explanation: The middle node of the list is node 3. Example 2: Input: head = [1,2,3,4,5,6] Output: [4,5,6] Explanation: Since the list has two middle nodes with values 3 and 4, we return the second one. Constraints: • The number of nodes in the list is in the range [1, 100]. • 1 <= Node.val <= 100 """ # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def middleNode(self, head: ListNode | None) -> ListNode | None: slow = fast = head while fast and fast.next: fast = fast.next.next slow = slow.next return slow