---
title: '71. Simplify Path'
description: You are given an absolute path for a Unix-style file system, which always begins with a slash '/'. Your task is to transform this absolute path into its simplified canonical path
icon: dot
topics:
  - { name: "String", slug: "string" }
  - { name: "Stack", slug: "stack" }
issue: "https://github.com/prdlk/leetcode/issues/70"
sidebar:
  label: 'Simplify Path'
  badge: 'Medium'
---

### Example 1:
- Input: `path = "/home/"`
- Output: `"/home"`
- Explanation: The trailing slash should be removed.

### Example 2:
- Input: `path = "/home//foo/"`
- Output: `"/home/foo"`
- Explanation: Multiple consecutive slashes are replaced by a single one.

### Example 3:
- Input: `path = "/home/user/Documents/../Pictures"`
- Output: `"/home/user/Pictures"`
- Explanation: A double period ".." refers to the directory up a level (the parent directory).

### Example 4:
- Input: `path = "/../"`
- Output: `"/"`
- Explanation: Going one level up from the root directory is not possible.

### Example 5:
- Input: `path = "/.../a/../b/c/../d/./"`
- Output: `"/.../b/d"`
- Explanation: "..." is a valid name for a directory in this problem.

### Constraints:

- `1 <= path.length <= 3000`
- `path` consists of English letters, digits, period '.', slash '/' or '_'.
- `path` is a valid absolute Unix path.

## Solution

```py
class Solution:
    def simplifyPath(self, path: str) -> str:
        stack = []
        segments = [item for item in path.split("/") if item]

        for p in segments:
            if stack and p == "..":
                stack.pop()
            elif not stack and p == ".." or p == ".":
                continue
            else:
                stack.append(p)

        return "/" + "/".join(stack)
```