feat(work): add Partition List solution stub

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Prad Nukala committed 2026-10-14 15:52:06 -04:00
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"""
86. Partition List
Difficulty: Medium
https://leetcode.com/problems/partition-list/
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Given the head of a linked list and a value x, partition it such that
all nodes less than x come before nodes greater than or equal to x.
You should preserve the original relative order of the nodes in each
of the two partitions.
Example 1:
Input: head = [1,4,3,2,5,2], x = 3
Output: [1,2,2,4,3,5]
Example 2:
Input: head = [2,1], x = 2
Output: [1,2]
Constraints:
• The number of nodes in the list is in the range [0, 200].
• -100 <= Node.val <= 100
• -200 <= x <= 200
"""
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def partition(self, head: ListNode | None, x: int) -> ListNode | None: