feat(work): add solution for LeetCode 36 Valid Sudoku

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Prad Nukala committed 2026-10-13 15:34:15 -04:00
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"""
36. Valid Sudoku
Difficulty: Medium
https://leetcode.com/problems/valid-sudoku/
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Determine if a 9 x 9 Sudoku board is valid. Only the filled cells
need to be validated according to the following rules:
• Each row must contain the digits 1-9 without repetition.
• Each column must contain the digits 1-9 without repetition.
• Each of the nine 3 x 3 sub-boxes of the grid must contain the
digits 1-9 without repetition.
Note:
• A Sudoku board (partially filled) could be valid but is not
necessarily solvable.
• Only the filled cells need to be validated according to the
mentioned rules.
Example 1:
Input: board =
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: true
Example 2:
Input: board =
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left
corner being modified to 8. Since there are two 8's in the top left
3x3 sub-box, it is invalid.
Constraints:
• board.length == 9
• board[i].length == 9
• board[i][j] is a digit 1-9 or '.'.
"""
import collections
class Solution:
def isValidSudoku(self, board: list[list[str]]) -> bool:
cols = collections.defaultdict(set)
rows = collections.defaultdict(set)
squares = collections.defaultdict(set) # (r/3, c/3)
for r in range(9):
for c in range(9):
if board[r][c] == ".":
continue
if (
board[r][c] in rows[r]
or board[r][c] in cols[c]
or board[r][c] in squares[(r // 3, c // 3)]
):
return False
cols[c].add(board[r][c])
rows[r].add(board[r][c])
squares[(r // 3, c // 3)].add(board[r][c])
return True