chore: clean up content phase organization

apps/docs/content/(01-linear-structures)/hash-table/1-two-sum.mdx

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+---
+title: '1. Two Sum'
+description: You are given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target
+sidebar:
+  label: 'Two Sum'
+  badge: 'Easy'
+---
+
+<Badge variant="accent">Array</Badge>
+
+::::warning
+Can you come up with an algorithm that is less than O(n^2) time complexity?
+::::
+
+### Example 1:
+- Input: `nums = [2,7,11,15], target = 9`
+- Output: `[0,1]`
+- Explanation: Because `nums[0] + nums[1]` == `9`, we return [0, 1].
+
+### Example 2:
+- Input: `nums = [3,2,4], target = 6`
+- Output: `[1,2]`
+
+### Example 3:
+- Input: `nums = [3,3], target = 6`
+- Output: `[0,1]`
+
+### Constraints:
+
+- `2 <= nums.length <= 10^4`
+- `-10^9 <= nums[i] <= 10^9`
+- `-10^9 <= target <= 10^9`
+- Only one valid answer exists.
+
+## Approach
+
+```mermaid
+flowchart TD
+  S(["twoSum(nums, target)"]) --> I["seen = {} — value to index"]
+  I --> L{"more (i, num) in nums?"}
+  L -- no --> E(["return []"])
+  L -- yes --> C["complement = target - num"]
+  C --> H{"complement in seen?"}
+  H -- yes --> R(["return [seen[complement], i]"])
+  H -- no --> W["seen[num] = i"]
+  W --> L
+```
+
+## Solution
+
+```py
+class Solution:
+    def twoSum(self, nums: List[int], target: int) -> List[int]:
+        seen = {}
+        for i, num in enumerate(nums):
+            complement = target - num
+            if complement in seen:
+                return [seen[complement], i]
+            seen[num] = i
+        return []
+```
+
+## Explanation
+
+<YouTube id="KLlXCFG5TnA" title="Two Sum - Leetcode 1 - HashMap - Python" />