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feat(work): implement insert interval solution
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@@ -23,7 +23,7 @@ Return intervals after the insertion.
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Note that you don't need to modify intervals in-place. You can make a
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Note that you don't need to modify intervals in-place. You can make a
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new array and return it.
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new array and return it.
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Example 1:
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Example 1:
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@@ -38,23 +38,44 @@ Output: [[1,2],[3,10],[12,16]]
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Explanation: Because the new interval [4,8] overlaps with
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Explanation: Because the new interval [4,8] overlaps with
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[3,5],[6,7],[8,10].
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[3,5],[6,7],[8,10].
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Constraints:
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Constraints:
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• 0 <= intervals.length <= 10^4
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• 0 <= intervals.length <= 10^4
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• intervals[i].length == 2
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• intervals[i].length == 2
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• 0 <= starti <= endi <= 10^5
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• 0 <= starti <= endi <= 10^5
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• intervals is sorted by starti in ascending order.
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• intervals is sorted by starti in ascending order.
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• newInterval.length == 2
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• newInterval.length == 2
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• 0 <= start <= end <= 10^5
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• 0 <= start <= end <= 10^5
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"""
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"""
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class Solution:
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class Solution:
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def insert(self, intervals: list[list[int]], newInterval: list[int]) -> list[list[int]]:
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def insert(
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self, intervals: list[list[int]], newInterval: list[int]
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) -> list[list[int]]:
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result = []
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i, n = 0, len(intervals)
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start, end = newInterval
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# Everything before
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while i < n and intervals[i][1] < start:
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result.append(intervals[i])
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i += 1
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# Everything merged
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while i < n and intervals[i][0] <= end:
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start = min(start, intervals[i][0])
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end = max(end, intervals[i][1])
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i += 1
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result.append([start, end])
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# Everything after
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result.extend(intervals[i:])
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return result
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