feat: refactored docs structure

docs/(05-decision-space)/greedy/(problems)/55_jump-game.mdx

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+---
+title: '55. Jump Game'
+description: You are given an integer array nums. You are initially positioned at the array's first index, and each element in the array represents your maximum jump length at that position
+icon: dot
+topics:
+  - { name: "Array", slug: "array" }
+  - { name: "Dynamic Programming", slug: "dynamic-programming" }
+  - { name: "Greedy", slug: "greedy" }
+issue: "https://github.com/prdlk/leetcode/issues/175"
+sidebar:
+  label: 'Jump Game'
+  badge: 'Medium'
+---
+
+### Example 1:
+- Input: `nums = [2,3,1,1,4]`
+- Output: `true`
+- Explanation: Jump `1` step from index `0` to `1`, then `3` steps to the last index.
+
+### Example 2:
+- Input: `nums = [3,2,1,0,4]`
+- Output: `false`
+- Explanation: You will always arrive at index `3` no matter what. Its maximum jump length is `0`, which makes it impossible to reach the last index.
+
+### Constraints:
+
+- `1 <= nums.length <= 10^4`
+- `0 <= nums[i] <= 10^5`
+
+## Solution
+
+```py
+class Solution:
+    def canJump(self, nums: list[int]) -> bool:
+        best, last = nums[0], len(nums) - 1
+
+        for i in range(last):
+            if i > best:
+                return False
+            else:
+                pos = nums[i] + i
+                best = max(best, pos)
+
+        return best >= last
+```