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docs(docs): add meta files and reorganize topics with updated badges and directory structure
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---
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title: '150. Evaluate Reverse Polish Notation'
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description: You are given an array of strings tokens that represents an arithmetic expression in a Reverse Polish Notation
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sidebar:
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label: 'Evaluate Reverse Polish Notation'
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badge: 'Medium'
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---
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<Badge variant="accent">Array</Badge>
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### Example 1:
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- Input: `tokens = ["2","1","+","3","*"]`
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- Output: `9`
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- Explanation: `((2 + 1`) * `3`) = `9`
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### Example 2:
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- Input: `tokens = ["4","13","5","/","+"]`
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- Output: `6`
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- Explanation: `(4 + (13 / 5`)) = `6`
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### Example 3:
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- Input: `tokens = ["10","6","9","3","+","-11","*","/","*","17","+","5","+"]`
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- Output: `22`
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- Explanation: `((10 * (6 / ((9 + 3`) * `-11`))) + `17`) + `5 = ((10 * (6 / (12 * -11`))) + `17`) + `5 = ((10 * (6 / -132`)) + `17`) + `5 = ((10 * 0`) + `17`) + `5 = (0 + 17`) + `5 = 17 + 5 = 22`
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### Constraints:
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- `1 <= tokens.length <= 10^4`
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- `tokens[i]` is either an operator: "+", "-", "*", or "/", or an integer in the range [-200, 200].
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## Approach
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```mermaid
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flowchart TD
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S(["evalRPN(tokens)"]) --> I["stack = [], operations = + - * /"]
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I --> L{"more token c?"}
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L -- no --> E(["return stack[0]"])
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L -- yes --> Q{"c is an operator?"}
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Q -- no --> N["stack.append(int(c))"]
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N --> L
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Q -- yes --> P["y = stack.pop(), x = stack.pop() — order matters"]
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P --> C["stack.append(operations[c](x, y))"]
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C --> L
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```
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## Solution
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```py
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class Solution:
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def evalRPN(self, tokens: List[str]) -> int:
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stack = []
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operations = {
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"+": lambda x, y: int(x + y),
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"-": lambda x, y: int(x - y),
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"*": lambda x, y: int(x * y),
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"/": lambda x, y: int(x / y),
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}
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for c in tokens:
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if c in operations:
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y = stack.pop()
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x = stack.pop()
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calc_func = operations[c]
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result = calc_func(x, y)
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stack.append(result)
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else:
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stack.append(int(c))
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return stack[0]
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```
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## Explanation
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<YouTube id="iu0082c4HDE" title="Evaluate Reverse Polish Notation - Leetcode 150 - Python" />
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---
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title: '20. Valid Parentheses'
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description: Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid
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sidebar:
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label: 'Valid Parentheses'
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badge: 'Easy'
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---
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<Badge variant="accent">String</Badge>
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### Example 1:
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- Input: `s = "()"`
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- Output: `true`
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### Example 2:
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- Input: `s = "()[]{}"`
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- Output: `true`
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### Example 3:
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- Input: `s = "(]"`
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- Output: `false`
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### Example 4:
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- Input: `s = "([])"`
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- Output: `true`
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### Example 5:
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- Input: `s = "([)]"`
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- Output: `false`
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### Constraints:
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- `1 <= s.length <= 10^4`
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- `s` consists of parentheses only '()[]{}'.
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## Approach
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```mermaid
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flowchart TD
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S(["isValid(s)"]) --> I["stack = [], pairs = closer to opener"]
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I --> L{"more char c?"}
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L -- no --> Z{"stack empty?"}
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Z -- yes --> T(["return True"])
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Z -- no --> U(["return False — unclosed openers left"])
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L -- yes --> Q{"c is a closer?"}
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Q -- no --> A["stack.append(c) — it is an opener"]
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A --> L
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Q -- yes --> M{"stack non-empty and pairs[c] == stack[-1]?"}
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M -- yes --> P["stack.pop() — matched"]
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P --> L
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M -- no --> F(["return False — mismatch"])
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```
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## Solution
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```py
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class Solution:
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def isValid(self, s: str) -> bool:
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stack = []
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pairs = {")": "(", "]": "[", "}": "{"}
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for c in s:
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if c in pairs:
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if stack and pairs[c] == stack[-1]:
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stack.pop()
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else:
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return False
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else:
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stack.append(c)
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return True if not stack else False
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```
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## Explanation
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<YouTube id="WTzjTskDFMg" title="Valid Parentheses - Stack - Leetcode 20 - Python" />
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@@ -0,0 +1,3 @@
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import { defineMeta } from "blume";
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export default defineMeta({ title: "Stack", order: 6 });
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