feat: refactored docs structure

apps/docs/content/(01-linear-structures)/two-pointers/(problems)/189_rotate-array.mdx

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+---
+title: '189. Rotate Array'
+description: Given an integer array nums, rotate the array to the right by k steps, where k is non-negative
+icon: dot
+topics:
+  - { name: "Array", slug: "array" }
+  - { name: "Math", slug: "math" }
+  - { name: "Two Pointers", slug: "two-pointers" }
+issue: "https://github.com/prdlk/leetcode/issues/47"
+sidebar:
+  label: 'Rotate Array'
+  badge: 'Medium'
+---
+
+### Example 1:
+- Input: `nums = [1,2,3,4,5,6,7], k = 3`
+- Output: `[5,6,7,1,2,3,4]`
+- Explanation: rotate `1` steps to the right: `[7,1,2,3,4,5,6]` rotate `2` steps to the right: `[6,7,1,2,3,4,5]` rotate `3` steps to the right: `[5,6,7,1,2,3,4]`
+
+### Example 2:
+- Input: `nums = [-1,-100,3,99], k = 2`
+- Output: `[3,99,-1,-100]`
+- Explanation: rotate `1` steps to the right: `[99,-1,-100,3]` rotate `2` steps to the right: `[3,99,-1,-100]`
+
+### Constraints:
+
+- `1 <= nums.length <= 10^5`
+- `-2^31 <= nums[i] <= 2^31 - 1`
+- `0 <= k <= 10^5`
+- Try to come up with as many solutions as you can. There are at least three different ways to solve this problem.
+- Could you do it in-place with O(1) extra space?
+
+## Solution
+
+```py
+class Solution:
+    def rotate(self, nums: list[int], k: int) -> None:
+        N = len(nums) - 1
+        cut = k % len(nums)
+
+        def reverse(l, r):
+            while l <= r:
+                nums[l], nums[r] = nums[r], nums[l]
+                l += 1
+                r -= 1
+
+        reverse(0, N)
+        reverse(0, cut - 1)
+        reverse(cut, N)
+```