feat: refactored docs structure

apps/docs/content/(01-linear-structures)/two-pointers/(problems)/11_container-with-most-water.mdx

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+---
+title: '11. Container With Most Water'
+description: You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the i^th line are (i, 0) and (i, height[i])
+icon: dot
+topics:
+  - { name: "Array", slug: "array" }
+  - { name: "Two Pointers", slug: "two-pointers" }
+  - { name: "Greedy", slug: "greedy" }
+video: "UuiTKBwPgAo"
+issue: "https://github.com/prdlk/leetcode/issues/44"
+sidebar:
+  label: 'Container With Most Water'
+  badge: 'Medium'
+---
+
+::::warning
+Notice that you may not slant the container.
+::::
+
+### Example 1:
+- Input: `height = [1,8,6,2,5,4,8,3,7]`
+- Output: `49`
+- Explanation: The above vertical lines are represented by array `[1,8,6,2,5,4,8,3,7]`. In this case, the max area of water (blue section) the container can contain is `49`.
+
+### Example 2:
+- Input: `height = [1,1]`
+- Output: `1`
+
+### Constraints:
+
+- `n == height.length`
+- `2 <= n <= 10^5`
+- `0 <= height[i] <= 10^4`
+
+## Approach
+
+```mermaid
+flowchart TD
+  S(["maxArea(height)"]) --> I["res = 0, left = 0, right = len - 1"]
+  I --> W{"left < right?"}
+  W -- no --> E(["return res"])
+  W -- yes --> A["area = (right - left) * min(height[left], height[right])"]
+  A --> M["res = max(res, area)"]
+  M --> C{"height[left] < height[right]?"}
+  C -- yes --> L["left += 1 — drop the shorter wall"]
+  C -- no --> R["right -= 1 — drop the shorter wall"]
+  L --> W
+  R --> W
+```
+
+## Solution
+
+```py
+class Solution:
+    def maxArea(self, height: List[int]) -> int:  # noqa: F821
+        res = 0
+        left = 0
+        right = len(height) - 1
+
+        while left < right:
+            area = (right - left) * min(height[left], height[right])
+            res = max(res, area)
+            if height[left] < height[right]:
+                left += 1
+            else:
+                right -= 1
+
+        return res
+```