feat(work): add sliding window solution for maximum average subarray and implement longest consecutive sequence

work/1/Easy/Array/643.maximum-average-subarray-i.py

@@ -39,4 +39,15 @@ Constraints:
 
 class Solution:
     def findMaxAverage(self, nums: list[int], k: int) -> float:
-        maxAvg = 0
+        window_sum = 0
+        for i in range(k):
+            window_sum += nums[i]
+        largest = window_sum
+
+        for right in range(k, len(nums)):
+            left = right - k
+            window_sum -= nums[left]
+            window_sum += nums[right]
+            largest = max(largest, window_sum)
+
+        return largest / k

work/1/Medium/Array/128.longest-consecutive-sequence.py

@@ -0,0 +1,57 @@
+"""
+128. Longest Consecutive Sequence
+Difficulty: Medium
+https://leetcode.com/problems/longest-consecutive-sequence/
+
+──────────────────────────────────────────────────
+
+Given an unsorted array of integers nums, return the length of the
+longest consecutive elements sequence.
+
+You must write an algorithm that runs in O(n) time.
+
+
+
+Example 1:
+
+Input: nums = [100,4,200,1,3,2]
+Output: 4
+Explanation: The longest consecutive elements sequence is [1, 2, 3,
+4]. Therefore its length is 4.
+
+Example 2:
+
+Input: nums = [0,3,7,2,5,8,4,6,0,1]
+Output: 9
+
+Example 3:
+
+Input: nums = [1,0,1,2]
+Output: 3
+
+
+
+Constraints:
+
+        • 0 <= nums.length <= 10^5
+
+        • -10^9 <= nums[i] <= 10^9
+"""
+
+
+class Solution:
+    def longestConsecutive(self, nums: list[int]) -> int:
+        seen = set(nums)
+        best = 0
+
+        for n in seen:
+            if n - 1 in seen:
+                continue
+
+            length = 1
+            while length + n in seen:
+                length += 1
+
+            best = max(length, best)
+
+        return best