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+"""
+525. Contiguous Array
+Difficulty: Medium
+https://leetcode.com/problems/contiguous-array/
+
+──────────────────────────────────────────────────
+
+Given a binary array nums, return the maximum length of a contiguous
+subarray with an equal number of 0 and 1.
+
+
+
+Example 1:
+
+Input: nums = [0,1]
+Output: 2
+Explanation: [0, 1] is the longest contiguous subarray with an equal
+number of 0 and 1.
+
+Example 2:
+
+Input: nums = [0,1,0]
+Output: 2
+Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with
+equal number of 0 and 1.
+
+Example 3:
+
+Input: nums = [0,1,1,1,1,1,0,0,0]
+Output: 6
+Explanation: [1,1,1,0,0,0] is the longest contiguous subarray with
+equal number of 0 and 1.
+
+
+
+Constraints:
+
+        • 1 <= nums.length <= 10^5
+
+        • nums[i] is either 0 or 1.
+"""
+
+
+class Solution:
+    def findMaxLength(self, nums: List[int]) -> int:
+        map = {0: -1}
+        count = 0
+        longest = 0
+
+        for i, num in enumerate(nums):
+            count += 1 if num == 1 else -1
+
+            if count in map:
+                longest = max(longest, i - map[count])
+            else:
+                map[count] = i
+
+        return longest