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docs(docs): add 143 Reorder List documentation
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---
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title: '143. Reorder List'
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description: 'You are given the head of a singly linked-list. The list can be represented as:'
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icon: dot
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topics:
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- { name: "Linked List", slug: "linked-list" }
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- { name: "Two Pointers", slug: "two-pointers" }
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- { name: "Stack", slug: "stack" }
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- { name: "Recursion", slug: "recursion" }
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issue: "https://github.com/prdlk/leetcode/issues/81"
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sidebar:
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label: 'Reorder List'
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badge: 'Medium'
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---
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### Example 1:
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- Input: `head = [1,2,3,4]`
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- Output: `[1,4,2,3]`
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### Example 2:
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- Input: `head = [1,2,3,4,5]`
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- Output: `[1,5,2,4,3]`
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### Constraints:
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- The number of nodes in the list is in the range [1, 5 * 10^4].
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- `1 <= Node.val <= 1000`
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## Solution
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```py
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution:
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def reorderList(self, head: ListNode | None) -> None:
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# Find middle
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slow, fast = head, head.next
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while fast and fast.next:
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slow = slow.next
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fast = fast.next.next
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# Reverse second half
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second = slow.next
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prev = slow.next = None
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while second:
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tmp = second.next
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second.next = prev
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prev = second
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second = tmp
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# merge two halfs
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first, second = head, prev
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while second:
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tmp1, tmp2 = first.next, second.next
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first.next = second
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second.next = tmp1
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first, second = tmp1, tmp2
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```
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