docs(docs): migrate to array based folder structure

docs/array/1365.mdx

@@ -0,0 +1,55 @@
+---
+title: LC-1365
+description: How Many Numbers Are Smaller Than the Current Number
+---
+
+## Examples
+
+| Input            | Output               |
+| ---------------- | -------------------- |
+| `[8,1,2,2,3]`    | `[4,0,1,1,3]`        |
+| `[6,5,4,8]`      | `[2,1,0,3]`          |
+| `[7,7,7,7]`      | `[0,0,0,0]`          |
+
+## Hints
+
+<Accordions type="single">
+  <Accordion title="Constraints">
+    Constraints:
+     • `2 <= nums.length <= 500`
+     • `0 <= nums[i] <= 100`
+  </Accordion>
+  <Accordion title="Problem Statement">
+    Given the array nums, for each `nums[i]` find out how many numbers in the array are smaller than it. 
+    That is, for each `nums[i]` you have to count the number of valid `j`'s such that `j != i` and `nums[j] < nums[i]`.
+  </Accordion>
+</Accordions>
+
+## Solution
+
+```js
+/**
+ * @param {number[]} nums
+ * @return {number[]}
+ */
+
+var smallerNumbersThanCurrent = function (nums) {
+  // Default for Hammer
+  const freq = {};
+  for (let n of nums) freq[n] = (freq[n] || 0) + 1;
+  const sorted = Object.keys(freq).sort((a, b) => a - b);
+
+  // Problem Specific
+  let count = 0;
+  let smaller = {};
+
+  // Iterate over sorted.
+  for (let num of sorted) {
+    smaller[num] = count;
+    count += freq[num];
+  }
+
+  // Map output
+  return nums.map((n) => smaller[n]);
+};
+```