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leetcode/work/1/Medium/String/71.simplify-path.py
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"""
71. Simplify Path
Difficulty: Medium
https://leetcode.com/problems/simplify-path/
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You are given an absolute path for a Unix-style file system, which
always begins with a slash '/'. Your task is to transform this
absolute path into its simplified canonical path.
The rules of a Unix-style file system are as follows:
• A single period '.' represents the current directory.
• A double period '..' represents the previous/parent directory.
• Multiple consecutive slashes such as '//' and '///' are treated as
a single slash '/'.
• Any sequence of periods that does not match the rules above should
be treated as a valid directory or file name. For example, '...' and
'....' are valid directory or file names.
The simplified canonical path should follow these rules:
• The path must start with a single slash '/'.
• Directories within the path must be separated by exactly one slash
'/'.
• The path must not end with a slash '/', unless it is the root
directory.
• The path must not have any single or double periods ('.' and '..')
used to denote current or parent directories.
Return the simplified canonical path.
Example 1:
Input: path = "/home/"
Output: "/home"
Explanation:
The trailing slash should be removed.
Example 2:
Input: path = "/home//foo/"
Output: "/home/foo"
Explanation:
Multiple consecutive slashes are replaced by a single one.
Example 3:
Input: path = "/home/user/Documents/../Pictures"
Output: "/home/user/Pictures"
Explanation:
A double period ".." refers to the directory up a level (the parent
directory).
Example 4:
Input: path = "/../"
Output: "/"
Explanation:
Going one level up from the root directory is not possible.
Example 5:
Input: path = "/.../a/../b/c/../d/./"
Output: "/.../b/d"
Explanation:
"..." is a valid name for a directory in this problem.
Constraints:
• 1 <= path.length <= 3000
• path consists of English letters, digits, period '.', slash '/' or
'_'.
• path is a valid absolute Unix path.
"""
class Solution:
def simplifyPath(self, path: str) -> str:
stack = []
segments = [item for item in path.split("/") if item]
for p in segments:
if stack and p == "..":
stack.pop()
elif not stack and p == ".." or p == ".":
continue
else:
stack.append(p)
return "/" + "/".join(stack)