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44 lines
989 B
Python
44 lines
989 B
Python
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86. Partition List
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Difficulty: Medium
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https://leetcode.com/problems/partition-list/
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──────────────────────────────────────────────────
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Given the head of a linked list and a value x, partition it such that
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all nodes less than x come before nodes greater than or equal to x.
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You should preserve the original relative order of the nodes in each
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of the two partitions.
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Example 1:
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Input: head = [1,4,3,2,5,2], x = 3
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Output: [1,2,2,4,3,5]
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Example 2:
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Input: head = [2,1], x = 2
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Output: [1,2]
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Constraints:
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• The number of nodes in the list is in the range [0, 200].
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• -100 <= Node.val <= 100
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• -200 <= x <= 200
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"""
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# Definition for singly-linked list.
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# class ListNode:
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# def __init__(self, val=0, next=None):
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# self.val = val
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# self.next = next
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class Solution:
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def partition(self, head: ListNode | None, x: int) -> ListNode | None:
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