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43 lines
1.1 KiB
Plaintext
43 lines
1.1 KiB
Plaintext
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---
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title: '224. Basic Calculator'
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description: Given a string s representing a valid expression, implement a basic calculator to evaluate it, and return the result of the evaluation
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icon: dot
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topics:
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- { name: "Math", slug: "math" }
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- { name: "String", slug: "string" }
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- { name: "Stack", slug: "stack" }
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- { name: "Recursion", slug: "recursion" }
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issue: "https://github.com/prdlk/leetcode/issues/71"
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sidebar:
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label: 'Basic Calculator'
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badge: 'Hard'
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---
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### Example 1:
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- Input: `s = "1 + 1"`
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- Output: `2`
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### Example 2:
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- Input: `s = " 2-1 + 2 "`
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- Output: `3`
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### Example 3:
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- Input: `s = "(1+(4+5+2)-3)+(6+8)"`
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- Output: `23`
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### Constraints:
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- `1 <= s.length <= 3 * 10^5`
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- `s` consists of digits, '+', '-', '(', ')', and ' '.
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- `s` represents a valid expression.
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- '+' is not used as a unary operation (i.e., "+1" and "+(2 + 3)" is invalid).
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- '-' could be used as a unary operation (i.e., "-1" and "-(2 + 3)" is valid).
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- There will be no two consecutive operators in the input.
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- Every number and running calculation will fit in a signed 32-bit integer.
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## Solution
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```py
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class Solution:
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def calculate(self, s: str) -> int:
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```
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