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45 lines
1.6 KiB
Plaintext
45 lines
1.6 KiB
Plaintext
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---
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title: '901. Online Stock Span'
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description: Design an algorithm that collects daily price quotes for some stock and returns the span of that stock's price for the current day
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icon: dot
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topics:
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- { name: "Stack", slug: "stack" }
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- { name: "Design", slug: "design" }
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- { name: "Monotonic Stack", slug: "monotonic-stack" }
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- { name: "Data Stream", slug: "data-stream" }
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issue: "https://github.com/prdlk/leetcode/issues/75"
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sidebar:
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label: 'Online Stock Span'
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badge: 'Medium'
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---
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### Example 1:
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- Input: ``
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- Output: ``
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- Explanation: Input ["StockSpanner", "next", "next", "next", "next", "next", "next", "next"] `[[]`, `[100]`, `[80]`, `[60]`, `[70]`, `[60]`, `[75]`, [85]] Output [null, `1`, `1`, `1`, `2`, `1`, `4`, 6] Explanation StockSpanner stockSpanner = new StockSpanner(); stockSpanner.next(100); // return `1` stockSpanner.next(80); // return `1` stockSpanner.next(60); // return `1` stockSpanner.next(70); // return `2` stockSpanner.next(60); // return `1` stockSpanner.next(75); // return `4`, because the last `4` prices (including today's `price` of `75`) were less than or equal to today's `price`. stockSpanner.next(85); // return `6`
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### Constraints:
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- `1 <= price <= 10^5`
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- At most 10^4 calls will be made to next.
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## Solution
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```py
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class StockSpanner:
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def __init__(self):
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self.stack = []
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def next(self, price: int) -> int:
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ans = 1
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while self.stack and self.stack[-1][0] <= price:
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ans += self.stack.pop()[1]
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self.stack.append([price, ans])
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return ans
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# Your StockSpanner object will be instantiated and called as such:
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# obj = StockSpanner()
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# param_1 = obj.next(price)
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```
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