fix(rank): keep every --exclude key out of the sweep when the list has spaces (#641)

* fix(rank): keep every --exclude key out of the sweep when the list has spaces

`sweep --exclude "a_b, c_d"` split on bare commas, so " c_d" matched no
entry and every key after the first was swept. On an --all run that
expired a re-scored entry whose fresh deadline apply then re-ranked, so
the report listed it as both expired and shortlisted. Strip each key.

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>

* changelog: place the #641 entry under [Unreleased]

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>

---------

Co-authored-by: Claude Opus 5.5 <noreply@anthropic.com>
Co-authored-by: Mads Lorentzen <madslorentzen_17@hotmail.com>

tools/rank_state.py

@@ -230,7 +230,9 @@ def cmd_candidates(args) -> int:
 def cmd_sweep(args) -> int:
     doc, seen = load_state(args.state)
     today = args.today
-    exclude = {k for k in (args.exclude or "").split(",") if k}
+    # "a_b, c_d" is as natural a comma-separated list as "a_b,c_d"; keys never
+    # carry surrounding whitespace, so a space must not un-exclude a key.
+    exclude = {k.strip() for k in (args.exclude or "").split(",") if k.strip()}
 
     expired, closing, unparseable, checked = [], [], [], 0
     for key, entry in seen.items():