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72 lines
1.4 KiB
Plaintext
72 lines
1.4 KiB
Plaintext
---
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title: '33. Search in Rotated Sorted Array'
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description: There is an integer array nums sorted in ascending order (with distinct values)
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sidebar:
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label: 'Search in Rotated Sorted Array'
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badge: 'Medium'
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---
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<Badge variant="accent">Binary Search</Badge>
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::::warning
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You must write an algorithm with O(log n) runtime complexity.
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::::
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### Example 1:
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- Input: `nums = [4,5,6,7,0,1,2], target = 0`
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- Output: `4`
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### Example 2:
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- Input: `nums = [4,5,6,7,0,1,2], target = 3`
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- Output: `-1`
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### Example 3:
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- Input: `nums = [1], target = 0`
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- Output: `-1`
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### Constraints:
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- `1 <= nums.length <= 5000`
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- `-10^4 <= nums[i] <= 10^4`
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- All values of `nums` are unique.
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- `nums` is an ascending array that is possibly rotated.
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- `-10^4 <= target <= 10^4`
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## Solution
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```js
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/**
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* @param {number[]} nums
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* @param {number} target
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* @return {number}
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*/
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var search = function(nums, target) {
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let l = 0, r = nums.length - 1;
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while (l <= r){
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let mid = Math.floor((l + r)/2);
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if (target === nums[mid]) {
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return mid
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}
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// Left sorted portion
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if (nums[l] <= nums[mid]){
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if (target > nums[mid] || target < nums[l]){
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l = mid + 1;
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}else{
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r = mid - 1;
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}
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}
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// Right sorted portion
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else{
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if(target < nums[mid] || target > nums[r]){
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r = mid - 1;
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}else{
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l = mid + 1;
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}
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}
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}
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return -1;
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};
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```
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