leetcode/docs/reference/15-first-unique-character-in-a-string.mdx

---
title: '387. First Unique Character in a String'
description: Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1
sidebar:
  badge: 'Easy'
---

<Badge variant="accent">Hash Table</Badge>

### Example 1:
- Input: `s = "leetcode"`
- Output: `0`
- Explanation: The character `'l'` at index `0` is the first character that does not occur at any other index.

### Example 2:
- Input: `s = "loveleetcode"`
- Output: `2`

### Example 3:
- Input: `s = "aabb"`
- Output: `-1`

### Constraints:

- `1 <= s.length <= 10^5`
- `s` consists of only lowercase English letters.

## Solution

```js
/**
 * @param {string} s
 * @return {number}
 */
var firstUniqChar = function (s) {
  const freq = {};
  for (let c of s) freq[c] = (freq[c] || 0) + 1;

  for (let i = 0; i < s.length; i++) {
    if (freq[s[i]] === 1) {
      return i;
    }
  }
  return -1;
};
```