""" 98. Validate Binary Search Tree Difficulty: Medium https://leetcode.com/problems/validate-binary-search-tree/ ────────────────────────────────────────────────── Given the root of a binary tree, determine if it is a valid binary search tree (BST). A valid BST is defined as follows: • The left subtree of a node contains only nodes with keys strictly less than the node's key. • The right subtree of a node contains only nodes with keys strictly greater than the node's key. • Both the left and right subtrees must also be binary search trees. Example 1: Input: root = [2,1,3] Output: true Example 2: Input: root = [5,1,4,null,null,3,6] Output: false Explanation: The root node's value is 5 but its right child's value is 4. Constraints: • The number of nodes in the tree is in the range [1, 10^4]. • -2^31 <= Node.val <= 2^31 - 1 """ # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def isValidBST(self, root: Optional[TreeNode]) -> bool: def valid(node, low, high): if not node: return True if not (low < node.val < high): return False return valid(node.left, low, node.val) and valid(node.right, node.val, high) return valid(root, float("-inf"), float("inf"))