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+"""
+226. Invert Binary Tree
+Difficulty: Easy
+https://leetcode.com/problems/invert-binary-tree/
+
+──────────────────────────────────────────────────
+
+Given the root of a binary tree, invert the tree, and return its root.
+
+
+
+Example 1:
+
+Input: root = [4,2,7,1,3,6,9]
+Output: [4,7,2,9,6,3,1]
+
+Example 2:
+
+Input: root = [2,1,3]
+Output: [2,3,1]
+
+Example 3:
+
+Input: root = []
+Output: []
+
+
+
+Constraints:
+
+        • The number of nodes in the tree is in the range [0, 100].
+
+        • -100 <= Node.val <= 100
+"""
+
+
+# Definition for a binary tree node.
+# class TreeNode:
+#     def __init__(self, val=0, left=None, right=None):
+#         self.val = val
+#         self.left = left
+#         self.right = right
+class Solution:
+    def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
+        if not root:
+            return None
+
+        left = self.invertTree(root.left)
+        right = self.invertTree(root.right)
+
+        root.left = right
+        root.right = left
+
+        return root