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docs: standardize accordion components in problem hints

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Prad Nukala
2026-07-14 11:10:30 -04:00
parent 3e4c8c7065
commit d322faa3a8
5 changed files with 30 additions and 30 deletions
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docs/array/1365.mdx
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@@ -13,17 +13,17 @@ description: How Many Numbers Are Smaller Than the Current Number
## Hints
<Accordions type="single">
<Accordion title="Constraints">
<Accordion type="single">
<AccordionItem title="Constraints">
Constraints:
• `2 <= nums.length <= 500`
• `0 <= nums[i] <= 100`
</Accordion>
<Accordion title="Problem Statement">
</AccordionItem>
<AccordionItem title="Problem Statement">
Given the array nums, for each `nums[i]` find out how many numbers in the array are smaller than it.
That is, for each `nums[i]` you have to count the number of valid `j`'s such that `j != i` and `nums[j] < nums[i]`.
</Accordion>
</Accordions>
</AccordionItem>
</Accordion>
## Solution
docs/array/1636.mdx
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@@ -13,18 +13,18 @@ description: Sort Array by Increasing Frequency
## Hints
<Accordions type="single">
<Accordion title="Constraints">
<Accordion type="single">
<AccordionItem title="Constraints">
Constraints:
• `1 <= nums.length <= 100`
• `-100 <= nums[i] <= 100`
</Accordion>
<Accordion title="Problem Statement">
</AccordionItem>
<AccordionItem title="Problem Statement">
Given an array of integers nums, sort the array in increasing order based on the frequency of the values.
If multiple values have the same frequency, sort them in decreasing order.
Return the sorted array.
</Accordion>
</Accordions>
</AccordionItem>
</Accordion>
## Solution
docs/array/347.mdx
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@@ -13,21 +13,21 @@ description: Top K Frequent Elements
## Hints
<Accordions type="single">
<Accordion title="Constraints">
<Accordion type="single">
<AccordionItem title="Constraints">
Constraints:
• `1 <= nums.length <= 10^5`
• `-10^4 <= nums[i] <= 10^4`
• `k` is in the range `[1, the number of unique elements in the array]`
• It is guaranteed that the answer is unique.
</Accordion>
<Accordion title="Problem Statement">
</AccordionItem>
<AccordionItem title="Problem Statement">
Given an integer array nums and an integer `k`, return the `k` most frequent elements.
You may return the answer in any order.
Follow up: Your algorithm's time complexity must be better than `O(n log n)`, where n is the array's size.
</Accordion>
</Accordions>
</AccordionItem>
</Accordion>
## Solution
docs/hash-table/387.mdx
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@@ -13,17 +13,17 @@ description: First Unique Character in a String
## Hints
<Accordions type="single">
<Accordion title="Constraints">
<Accordion type="single">
<AccordionItem title="Constraints">
Constraints:
• `1 <= s.length <= 10^5`
• `s` consists of only lowercase English letters.
</Accordion>
<Accordion title="Problem Statement">
</AccordionItem>
<AccordionItem title="Problem Statement">
Given a string `s`, find the first non-repeating character in it and return its index.
If it does not exist, return `-1`.
</Accordion>
</Accordions>
</AccordionItem>
</Accordion>
## Solution
docs/hash-table/451.mdx
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@@ -13,18 +13,18 @@ description: Sort Characters By Frequency
## Hints
<Accordions type="single">
<Accordion title="Constraints">
<Accordion type="single">
<AccordionItem title="Constraints">
Constraints:
• `1 <= s.length <= 5 * 10^5`
• `s` consists of uppercase and lowercase English letters and digits.
</Accordion>
<Accordion title="Problem Statement">
</AccordionItem >
<AccordionItem title="Problem Statement">
Given a string `s`, sort it in decreasing order based on the frequency of the characters.
The frequency of a character is the number of times it appears in the string.
Return the sorted string. If there are multiple answers, return any of them.
</Accordion>
</Accordions>
</AccordionItem >
</Accordion>
## Solution