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+"""
+35. Search Insert Position
+Difficulty: Easy
+https://leetcode.com/problems/search-insert-position/
+
+──────────────────────────────────────────────────
+
+Given a sorted array of distinct integers and a target value, return
+the index if the target is found. If not, return the index where it
+would be if it were inserted in order.
+
+You must write an algorithm with O(log n) runtime complexity.
+
+
+
+Example 1:
+
+Input: nums = [1,3,5,6], target = 5
+Output: 2
+
+Example 2:
+
+Input: nums = [1,3,5,6], target = 2
+Output: 1
+
+Example 3:
+
+Input: nums = [1,3,5,6], target = 7
+Output: 4
+
+
+
+Constraints:
+
+        • 1 <= nums.length <= 10^4
+
+        • -10^4 <= nums[i] <= 10^4
+
+        • nums contains distinct values sorted in ascending order.
+
+        • -10^4 <= target <= 10^4
+"""
+
+
+class Solution:
+    def searchInsert(self, nums: List[int], target: int) -> int:
+        l, r = 0, len(nums) - 1
+
+        while l <= r:
+            m = (l + r) // 2
+            if nums[m] == target:
+                return m
+            elif nums[m] < target:
+                l = m + 1
+            elif nums[m] > target:
+                r = m - 1
+
+        return (l + r) // 2 + 1