refactor(work): restructure solution directories with bucket level and add .gitkeep placeholders

work/1/Medium/Array/167.two-sum-ii-input-array-is-sorted.py

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+"""
+167. Two Sum II - Input Array Is Sorted
+Difficulty: Medium
+https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/
+
+──────────────────────────────────────────────────
+
+Given a 1-indexed array of integers numbers that is already sorted in
+non-decreasing order, find two numbers such that they add up to a
+specific target number. Let these two numbers be numbers[index1] and
+numbers[index2] where 1 <= index1 < index2 <= numbers.length.
+
+Return the indices of the two numbers index1 and index2, each
+incremented by one, as an integer array [index1, index2] of length 2.
+
+The tests are generated such that there is exactly one solution. You
+may not use the same element twice.
+
+Your solution must use only constant extra space.
+
+ 
+
+Example 1:
+
+Input: numbers = [2,7,11,15], target = 9
+Output: [1,2]
+Explanation: The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 =
+2. We return [1, 2].
+
+Example 2:
+
+Input: numbers = [2,3,4], target = 6
+Output: [1,3]
+Explanation: The sum of 2 and 4 is 6. Therefore index1 = 1, index2 =
+3. We return [1, 3].
+
+Example 3:
+
+Input: numbers = [-1,0], target = -1
+Output: [1,2]
+Explanation: The sum of -1 and 0 is -1. Therefore index1 = 1, index2
+= 2. We return [1, 2].
+
+ 
+
+Constraints:
+
+	• 2 <= numbers.length <= 3 * 10^4
+
+	• -1000 <= numbers[i] <= 1000
+
+	• numbers is sorted in non-decreasing order.
+
+	• -1000 <= target <= 1000
+
+	• The tests are generated such that there is exactly one solution.
+"""
+
+class Solution:
+    def twoSum(self, numbers: List[int], target: int) -> List[int]:
+        i = 0
+        j = len(numbers) - 1
+
+        while i < j:
+            c = numbers[i] + numbers[j]
+            if c == target:
+                return [i + 1, j + 1]
+            elif c < target:
+                i+=1
+            else:
+                j-=1
+        return []
+