refactor(work): restructure solution directories with bucket level and add .gitkeep placeholders

work/1/Easy/Array/217.contains-duplicate.js

@@ -0,0 +1,62 @@
+/*
+ * 217. Contains Duplicate
+ * Difficulty: Easy
+ * https://leetcode.com/problems/contains-duplicate/
+ * 
+ * ──────────────────────────────────────────────────
+ * 
+ * Given an integer array nums, return true if any value appears at
+ * least twice in the array, and return false if every element is
+ * distinct.
+ * 
+ *  
+ * 
+ * Example 1:
+ * 
+ * Input: nums = [1,2,3,1]
+ * 
+ * Output: true
+ * 
+ * Explanation:
+ * 
+ * The element 1 occurs at the indices 0 and 3.
+ * 
+ * Example 2:
+ * 
+ * Input: nums = [1,2,3,4]
+ * 
+ * Output: false
+ * 
+ * Explanation:
+ * 
+ * All elements are distinct.
+ * 
+ * Example 3:
+ * 
+ * Input: nums = [1,1,1,3,3,4,3,2,4,2]
+ * 
+ * Output: true
+ * 
+ *  
+ * 
+ * Constraints:
+ * 
+ * 	• 1 <= nums.length <= 10^5
+ * 
+ * 	• -10^9 <= nums[i] <= 10^9
+*/
+
+/**
+ * @param {number[]} nums
+ * @return {boolean}
+ */
+var containsDuplicate = function(nums) {
+  const freq = {};
+  for (let n of nums) {
+    freq[n] = (freq[n] || 0) + 1;
+    if (freq[n] >= 2) {
+      return true;
+    }
+  } 
+  return false;
+};