feat(work): add LeetCode solutions for 217, 271, and 98

This commit is contained in:
Prad Nukala
2026-09-05 13:37:53 -04:00
parent 9a2b80949b
commit 3e1a66eb37
3 changed files with 205 additions and 0 deletions
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"""
271. Encode and Decode Strings
Difficulty: Medium
https://leetcode.com/problems/encode-and-decode-strings/
──────────────────────────────────────────────────
Design an algorithm to encode a list of strings to a string. The
encoded string is then sent over the network and is decoded back to
the original list of strings.
Machine 1 (sender) has the function:
string encode(vector<string> strs) {
// ... your code
return encoded_string;
}
Machine 2 (receiver) has the function:
vector<string> decode(string s) {
//... your code
return strs;
}
So Machine 1 does:
string encoded_string = encode(strs);
and Machine 2 does:
vector<string> strs2 = decode(encoded_string);
strs2 in Machine 2 should be the same as strs in Machine 1.
Implement the encode and decode methods.
You are not allowed to solve the problem using any serialize methods
(such as eval).
Example 1:
Input: dummy_input = ["Hello","World"]
Output: ["Hello","World"]
Explanation:
Machine 1:
Codec encoder = new Codec();
String msg = encoder.encode(strs);
Machine 1 ---msg---> Machine 2
Machine 2:
Codec decoder = new Codec();
String[] strs = decoder.decode(msg);
Example 2:
Input: dummy_input = [""]
Output: [""]
Constraints:
• 1 <= strs.length <= 200
• 0 <= strs[i].length <= 200
• strs[i] contains any possible characters out of 256 valid ASCII
characters.
Follow up: Could you write a generalized algorithm to work on any
possible set of characters?
"""
class Codec:
def encode(self, strs: List[str]) -> str:
"""Encodes a list of strings to a single string.
"""
def decode(self, s: str) -> List[str]:
"""Decodes a single string to a list of strings.
"""
# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.decode(codec.encode(strs))
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"""
98. Validate Binary Search Tree
Difficulty: Medium
https://leetcode.com/problems/validate-binary-search-tree/
──────────────────────────────────────────────────
Given the root of a binary tree, determine if it is a valid binary
search tree (BST).
A valid BST is defined as follows:
• The left subtree of a node contains only nodes with keys strictly
less than the node's key.
• The right subtree of a node contains only nodes with keys strictly
greater than the node's key.
• Both the left and right subtrees must also be binary search trees.
Example 1:
Input: root = [2,1,3]
Output: true
Example 2:
Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value
is 4.
Constraints:
• The number of nodes in the tree is in the range [1, 10^4].
• -2^31 <= Node.val <= 2^31 - 1
"""
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isValidBST(self, root: Optional[TreeNode]) -> bool:
def valid(node, low, high):
if not node:
return True
if not (low < node.val < high):
return False
return valid(node.left, low, node.val) and valid(node.right, node.val, high)
return valid(root, float("-inf"), float("inf"))