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chore(Blind): add answer key and solutions for deduction problems
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/*
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* 451. Sort Characters By Frequency
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* Difficulty: Medium
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* https://leetcode.com/problems/sort-characters-by-frequency/
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*
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* ──────────────────────────────────────────────────
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*
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* Given a string s, sort it in decreasing order based on the frequency
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* of the characters. The frequency of a character is the number of times
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* it appears in the string.
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*
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* Return the sorted string. If there are multiple answers, return any
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* of them.
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*
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*
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*
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* Example 1:
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*
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* Input: s = "tree"
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* Output: "eert"
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* Explanation: 'e' appears twice while 'r' and 't' both appear once.
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* So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also
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* a valid answer.
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*
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* Example 2:
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*
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* Input: s = "cccaaa"
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* Output: "aaaccc"
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* Explanation: Both 'c' and 'a' appear three times, so both "cccaaa"
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* and "aaaccc" are valid answers.
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* Note that "cacaca" is incorrect, as the same characters must be
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* together.
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*
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* Example 3:
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*
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* Input: s = "Aabb"
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* Output: "bbAa"
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* Explanation: "bbaA" is also a valid answer, but "Aabb" is incorrect.
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* Note that 'A' and 'a' are treated as two different characters.
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*
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*
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*
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* Constraints:
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*
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* • 1 <= s.length <= 5 * 10^5
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*
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* • s consists of uppercase and lowercase English letters and digits.
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*/
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/**
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* @param {string} s
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* @return {string}
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*/
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var frequencySort = function (s) {
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// count the frequency of each character
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const freq = {};
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for (let c of s) freq[c] = (freq[c] || 0) + 1;
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// sort the characters by frequency
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return s
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.split("")
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.sort((a, b) => freq[b] - freq[a] || a.localeCompare(b))
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.join("");
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};
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