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leetcode/work/Medium/Array/2090.k-radius-subarray-averages.js
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/*
* 2090. K Radius Subarray Averages
* Difficulty: Medium
* https://leetcode.com/problems/k-radius-subarray-averages/
*
* ──────────────────────────────────────────────────
*
* You are given a 0-indexed array nums of n integers, and an integer k.
*
* The k-radius average for a subarray of nums centered at some index i
* with the radius k is the average of all elements in nums between the
* indices i - k and i + k (inclusive). If there are less than k elements
* before or after the index i, then the k-radius average is -1.
*
* Build and return an array avgs of length n where avgs[i] is the
* k-radius average for the subarray centered at index i.
*
* The average of x elements is the sum of the x elements divided by x,
* using integer division. The integer division truncates toward zero,
* which means losing its fractional part.
*
* • For example, the average of four elements 2, 3, 1, and 5 is (2 + 3
* + 1 + 5) / 4 = 11 / 4 = 2.75, which truncates to 2.
*
*
*
* Example 1:
*
* Input: nums = [7,4,3,9,1,8,5,2,6], k = 3
* Output: [-1,-1,-1,5,4,4,-1,-1,-1]
* Explanation:
* - avg[0], avg[1], and avg[2] are -1 because there are less than k
* elements before each index.
* - The sum of the subarray centered at index 3 with radius 3 is: 7 + 4
* + 3 + 9 + 1 + 8 + 5 = 37.
* Using integer division, avg[3] = 37 / 7 = 5.
* - For the subarray centered at index 4, avg[4] = (4 + 3 + 9 + 1 + 8 +
* 5 + 2) / 7 = 4.
* - For the subarray centered at index 5, avg[5] = (3 + 9 + 1 + 8 + 5 +
* 2 + 6) / 7 = 4.
* - avg[6], avg[7], and avg[8] are -1 because there are less than k
* elements after each index.
*
* Example 2:
*
* Input: nums = [100000], k = 0
* Output: [100000]
* Explanation:
* - The sum of the subarray centered at index 0 with radius 0 is:
* 100000.
* avg[0] = 100000 / 1 = 100000.
*
* Example 3:
*
* Input: nums = [8], k = 100000
* Output: [-1]
* Explanation:
* - avg[0] is -1 because there are less than k elements before and
* after index 0.
*
*
*
* Constraints:
*
* • n == nums.length
*
* • 1 <= n <= 10^5
*
* • 0 <= nums[i], k <= 10^5
*/
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var getAverages = function(nums, k) {
};