mirror of
https://github.com/prdlk/leetcode.git
synced 2026-09-17 15:36:26 +00:00
61 lines
1.5 KiB
Python
61 lines
1.5 KiB
Python
"""
|
|||
|
|
424. Longest Repeating Character Replacement
|
||
|
|
Difficulty: Medium
|
||
|
|
https://leetcode.com/problems/longest-repeating-character-replacement/
|
||
|
|
|
||
|
|
──────────────────────────────────────────────────
|
||
|
|
|
||
|
|
You are given a string s and an integer k. You can choose any
|
||
|
|
character of the string and change it to any other uppercase English
|
||
|
|
character. You can perform this operation at most k times.
|
||
|
|
|
||
|
|
Return the length of the longest substring containing the same letter
|
||
|
|
you can get after performing the above operations.
|
||
|
|
|
||
|
|
|
||
|
|
|
||
|
|
Example 1:
|
||
|
|
|
||
|
|
Input: s = "ABAB", k = 2
|
||
|
|
Output: 4
|
||
|
|
Explanation: Replace the two 'A's with two 'B's or vice versa.
|
||
|
|
|
||
|
|
Example 2:
|
||
|
|
|
||
|
|
Input: s = "AABABBA", k = 1
|
||
|
|
Output: 4
|
||
|
|
Explanation: Replace the one 'A' in the middle with 'B' and form
|
||
|
|
"AABBBBA".
|
||
|
|
The substring "BBBB" has the longest repeating letters, which is 4.
|
||
|
|
There may exists other ways to achieve this answer too.
|
||
|
|
|
||
|
|
|
||
|
|
|
||
|
|
Constraints:
|
||
|
|
|
||
|
|
• 1 <= s.length <= 10^5
|
||
|
|
|
||
|
|
• s consists of only uppercase English letters.
|
||
|
|
|
||
|
|
• 0 <= k <= s.length
|
||
|
|
"""
|
||
|
|
|
||
|
|
|
||
|
|
class Solution:
|
||
|
|
def characterReplacement(self, s: str, k: int) -> int:
|
||
|
|
count = {}
|
||
|
|
res = 0
|
||
|
|
|
||
|
|
l = 0
|
||
|
|
maxF = 0
|
||
|
|
for r, c in enumerate(s):
|
||
|
|
count[c] = 1 + count.get(c, 0)
|
||
|
|
maxF = max(maxF, count[c])
|
||
|
|
|
||
|
|
while (r - l + 1) - maxF > k:
|
||
|
|
count[s[l]] -= 1
|
||
|
|
l += 1
|
||
|
|
|
||
|
|
res = max(res, r - l + 1)
|
||
|
|
return res
|